To prepare 4.5L of a 1% solution, how many ml of water are needed if using a 50% dextrose solution?

To determine how many milliliters of water are needed to prepare a 1% solution from a 50% dextrose solution, it is essential to understand the concept of concentration and dilution.

First, a 1% solution means that there is 1 gram of solute (dextrose in this case) in 100 ml of the solution. For 4.5 liters (or 4500 ml) of a 1% solution, you would need:

[

1\text{g/100ml} \times 4500\text{ml} = 45\text{g of dextrose}

]

Next, since the starting solution is a 50% dextrose solution, it contains 50 grams of dextrose per 100 ml. To find out how much of the 50% solution is needed to obtain 45 grams of dextrose, we set up the equation:

[

\text{Amount of 50% solution (ml)} = \frac{45\text{g}}{0.50 \text{g/ml}} = 90\text{ml}

]

Now, we need to find out the total volume of the final 1