To prepare a 500mg dose of chlorpromazine using 25mg/mL stock solution, how many mL will be needed?

Study for the Pharmacy Technician Certification Board Math Exam. Prepare with flashcards and multiple choice questions, each question includes hints and explanations. Excel in your exam!

To determine how many milliliters of a 25 mg/mL stock solution are needed to prepare a 500 mg dose of chlorpromazine, you can use the formula:

Volume (mL) = Desired Dose (mg) / Concentration (mg/mL)

First, you need to plug in the values:

Desired Dose = 500 mg

Concentration = 25 mg/mL

Now, performing the calculation:

Volume (mL) = 500 mg / 25 mg/mL = 20 mL

This means that to achieve a total of 500 mg of chlorpromazine, you will need 20 mL of the 25 mg/mL stock solution. This calculation directly aligns with the requirement of preparing an accurate dose for patient care, ensuring that the technician successfully understands how to convert stock solution concentrations into measurable volumes needed for medication preparation.

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