What volume of purified water is needed to dilute an 8% solution to a final volume of 500ml?

To determine the volume of purified water needed to dilute an 8% solution to a final volume of 500 ml, we can start by calculating the amount of the active ingredient in the final solution.

An 8% solution means that there are 8 grams of solute in every 100 ml of solution. To find out how much solute is present in 500 ml of an 8% solution, we use the equation:

[

\text{Amount of solute} = \text{Concentration} \times \text{Volume} = 0.08 \times 500 \text{ml} = 40 \text{grams}

]

This tells us that in the final volume of 500 ml, we need 40 grams of the solute. Since we want the final volume to be 500 ml, and we already have 40 grams of the solute in the initial 8% solution, we now need to determine how much of the original 8% solution we need to use.

The volume of an 8% solution that contains 40 grams of solute can be found by rearranging the concentration formula:

[

\text{Volume of initial solution} = \frac{\text